Rep. Donalds Appointed to New Congressional Committee on Economic Disparity and Fairness in Growth
House Republican Leader Kevin McCarthy (CA-23) announced yesterday his nomination of Rep. Byron Donalds (FL-19) as a Member of Congress’ new Select Committee on Economic Disparity and Fairness Growth.
From Congressman Donalds:
“Ensuring that every American has access to the American Dream and economic prosperity is only possible in a free and capitalistic society that allows for equality of access to success, not by controlling outcomes through raising taxes, wealth distribution, and government dependence. I am grateful to Leader McCarthy for appointing me to this Select Committee and allowing me the opportunity to advocate for the policies that will empower Americans of all backgrounds: lower taxes, fewer regulations, less government interference, and pro-American energy policies.
“As a proud Floridian, I will bring the pro-growth, pro-small business, and pro-Floridian agenda that has attracted many people and businesses to the Sunshine State. My Democrat colleagues like to preach about income inequality and the so-called systemic racism rooted in our economic system, yet many of these issues derive from and thrive in America’s most liberal states and cities. I am determined to allow for an economic environment that encourages innovation, growth, and opportunity for all Americans to succeed.”
“My priorities on the select committee are to support all workers, empower families, and strengthen our economy with pro-growth legislation. Our nation is at a crossroads. We can continue down the current path of big government, socialist policies, or change course. I will advocate for policies to ensure everyone can sit down at the dinner table feeling financially secure. By prioritizing our workforce and getting government out of the way, we can create family-supporting jobs. I look forward to working with Byron to bring commonsense solutions to issues impacting rural, suburban, and urban communities,” said Ranking Member Bryan Steil.
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